Zoekresultaten

) + b cos (bτ))] k3 (τ) = 1 2a (1− exp (−2aτ)) k4 (τ) = 1 2 (a2 + b2) [a+ exp (−2aτ) (b sin (2bτ)− a cos (2bτ))] k5 (τ) = 1 2 (a2 + b2) [b− exp (−2aτ) (a sin (2bτ) + b cos (2bτ))] Again A(0) = 0 as →